Question

I’m just wondering if there is a quick way to echo undefined variables without getting a warning? (I can change error reporting level but I don’t want to.) The smallest I have so far is:

isset($variable)?$variable:''

I dislike this for a few reasons:

• It’s a bit ‘wordy’ and complex
• $variable is repeated
• The echoing of a blank string always kind of annoys me.
• My variable names will probably be longer, eg $arrayvar['parameter']

Answer 1

you could use the ifsetor() example taken from here:

function ifsetor(&$variable, $default = null) {     if (isset($variable)) {         $tmp = $variable;     } else {         $tmp = $default;     }     return $tmp; } 

for example:

echo ifsetor($variable); echo ifsetor($variable, 'default'); 

This does not generate a notice because the variable is passed by reference.