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Editorial Team
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Asked: 2026-06-16T13:26:48+00:00

I’m kinda going crazy about this problem. I can’t do it myself so I

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I’m kinda going crazy about this problem. I can’t do it myself so I need the community to help me get this thing solved. I’ve been spending hours on this because I didn’t know where to look. I now know a possible fix but it’s just messy (read on). I just need someone who knows more about this than I do.

This is my situation:

  • I want to use 2 or more mysql connections.
  • I use OOP

I have a class called dbase, it has two functions, setConnection and getConnection and two class variables called $connection and $dbaseName.

In my main project file I include dbase and create two objects:

  • dbase
  • maindbase

then I do:

$this->dbase->setConnection($server, $uname, $pword);
$this->maindbase->setConnection($server, $uname, $pword);

the setConnection function looks like this:

function setConnection ($server, $serv_Username, $serv_Password) {
    $this->connection = mysql_connect($server, $serv_Username, $serv_Password, true);
    // echo $this->connection . "<BR>";
}

I echo it to see the resourcenumber and added true to mysql_connect (and I know it’s deprecated since 5.5, I’m not here for that).

Now, as I understand OOP, the class variables are set per object. So $connection from dbase will never be the same as maindbase (unless, of course, I use the same credentials, but even then it will create a new link because of the $new_link option I enabled). They both have different resource ID’s.

My problem:

In class dbase I also have a function which runs a query like this:

$connection = $this->getConnection();
$dbase_name = $this->getDbaseName();
mysql_select_db($dbase_name, $connection); 
$q = "SELECT * FROM {$table_name} WHERE {$column} LIKE '{$value}'";
$result = mysql_query($q);

Now, when I use it like this, it will ALWAYS use the FIRST $connection that has been set in class dbase and it doesn’t matter which object this is, either object dbase or maindbase.

I get this error:

Table 'testdbase1.skye_domains' doesn't exist

object dbase is connected to testdbase1

object maindbase is connected to testdbase2

the above error I get when trying to select results using the maindbase object.

When I remove the $connection string from mysql_select_db it works perfectly because it will try to open a new connection as if using mysql_connect.

Why is this? This is impossible right? How can objectmaindbase have the same $connection as object dbase? They are in NO WAY connected to eachother… Is PHP somehow using a global mysql_connect variable or buffer which I’m not aware about?

I would like to keep using connectionstrings as this is just handy now and then. Leaving the $connection string out seems messy.

Does anybody have any suggestions I can try to make PHP (or my head) sane again?

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1 Answer

  1. Editorial Team

    Try to put echo $this->connection EVERYWHERE you use it. Also, create an “id” member and fill it with a unique value upon constructing a dbase-object and echo it along the value of $this->connection. This way you can track where what happens to your connection.

    And check if there’s maybe some place outside of the class that assigns $foo->connection. If you’re not using “private” on the members, you’re bound to have such problems when you e.g. forget to remove a hack or an experiment from unrelated parts of your code.

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