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Home/ Questions/Q 6662971
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T02:26:53+00:00 2026-05-26T02:26:53+00:00

I’m learning ANTLR by modifying the C grammar and trying something interests myself. The

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I’m learning ANTLR by modifying the C grammar and trying something interests myself. The C grammar I started with is from: http://www.antlr.org/grammar/1153358328744/C.g

Now I want to transform postfix_expression to its corresponding AST but haven’t known anything related to the transformation of the form xx (aa|bb|cc)* yy

...
unary_expression
  : postfix_expression
  | unary_operator^ unary_expression
  ;

postfix_expression
  : primary_expression
  ( '[' expression ']'
  | '(' ')'
  | '(' argument_expression_list ')'
  | '.' ID
  )*
  ;

unary_operator
  : '+'
  | '-'
  | '~'
  | '!'
  ;
...

Can you help me with this problem? You may just add some ^ and/or ! notations to the postfix_expression part in the grammar.

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  1. Editorial Team
    Editorial Team
    2026-05-26T02:26:54+00:00Added an answer on May 26, 2026 at 2:26 am

    Id’d go for something like this:

    grammar T;
    
    options {
      output=AST;
    }
    
    tokens {
      ROOT;
      MEMBER;
      INDEX;
      CALL;
    }
    
    parse
      :  unary_expression EOF -> ^(ROOT unary_expression)
      ;
    
    unary_expression
      :  postfix_expression
      |  unary_operator unary_expression -> ^(unary_operator unary_expression)
      ;
    
    postfix_expression
      :  primary_expression tail* -> ^(primary_expression tail*)
      ;
    
    tail
      :  '[' expression ']'                -> ^(INDEX expression)
      |  '(' argument_expression_list? ')' -> ^(CALL argument_expression_list?)
      |  '.' ID                            -> ^(MEMBER ID)
      ;
    
    primary_expression
      :  ID
      |  '(' expression ')' -> expression
      ;
    
    argument_expression_list
      :  expression (',' expression)* -> expression+
      ;
    
    unary_operator
      :  '+'
      |  '-'
      |  '~'
      |  '!'
      ;
    
    expression
      :  NUMBER
      |  ID
      ;
    
    NUMBER : '0'..'9'+;
    ID     : ('a'..'z' | 'A'..'Z')+;
    

    which will parse the input:

    a.b.c(foo,42)[123]
    

    into the following AST:

    enter image description here

    making it easy to evaluate the expression left to right.

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