Question

I’m learning haskell. I’m reading a string from a text file and need to make this string becomes a list of char.

The input file is this:

Individuo A; TACGATCAAAGCT 
Individuo B; AATCGCAT 
Individuo C; TAAATCCGATCAAAGAGAGGACTTA 

I need convert this string

S1 = "AAACCGGTTAAACCCGGGG"  in  S1 = 
["A","A","A","C","C","G","G","T","T","A","A","A","C","C","C","G","G","G","G"] 
or S1 = 
['A','A','A','C','C','G','G','T','T','A','A','A','C','C','C','G','G','G','G'] 

but they are separated by “;”

What should I do?

What can I do?

after getting two lists, I send them to this code:

lcsList :: Eq a => [a] -> [a] -> [a]
lcsList [] _ = []
lcsList _ [] = []
lcsList (x:xs) (y:ys) = if x == y
                          then x : lcsList xs ys
                          else
                            let lcs1 = lcsList (x:xs) ys
                                lcs2 = lcsList xs (y:ys)
                            in if (length lcs1) > (length lcs2)
                                  then lcs1
                                  else lcs2

Answer 1

A rough and ready way to split out each of those strings is with something like this – which you can try in ghci

let a = "Individuo A; TACGATCAAAGCT"
tail $ dropWhile (/= ' ') $ dropWhile (/= ';') a

which gives you:

"TACGATCAAAGCT"

And since a String is just a list of Char, this is the same as:

['T', 'A', 'C', 'G', ...