Question

I’m learning how to use python right now. I found a problem while learning about definitions that I don’t understand. I give a simple menu with choice 0-4. If the user chooses above 4, there supposed to receive a message that says “This is not a valid choice…”

However, if you input a value greater than or equal to 10, it doesn’t return anything but the menu…no message.

Thanks in Advance for Any Thoughts.

Here is My Code:

# Multitasker
# Allows User to Pick an Item that is Defined.

def exit():
    print("See You Later!")
def task1():
    print("This is Task 1!")
def task2():
    print("This is Task 2!")
def task3():
    print("This is Task 3!")
def task4():
    print("This is Task 4!")

choice = None
while choice != "0":
    print(
        """
        Multitask Selector

        0 - Quit
        1 - Task 1
        2 - Task 2
        3 - Task 3
        4 - Task 4
        """
        )

    choice = input("Pick a Task Between 1-4:\t#")
    print()

    # Exit
    if choice == "0":
        exit()

    # Task 1
    elif choice == "1":
        task1()

    # Task 2
    elif choice == "2":
        task2()

    # Task 3
    elif choice == "3":
        task3()

    # Task 4
    elif choice == "4":
        task4()

    # Not a Correct Selection
    elif choice > "4":
        print("That is not a valid choice.  Please Select a Task Between 1-4.")

Answer 1

You’re comparing choice, which is a string (I’m assuming Python 3 from your print functions), with “4”, also a string.

elif choice > "4":

This works lexicographically:

>>> '1' < '2'
True
>>> '1' < '100'
True
>>> '100' < '2'
True

If you want numerical comparisons, you have to turn choice into a number, e.g.

>>> int('1') > 4
False
>>> int('10') > 4
True
>>>