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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T22:17:07+00:00 2026-05-13T22:17:07+00:00

I’m learning Java here, and using a GLabel object. It’s in the ACM Graphics

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I’m learning Java here, and using a “GLabel” object. It’s in the ACM Graphics library, and you can read about it here:

http://jtf.acm.org/javadoc/student/acm/graphics/GLabel.html

In short, the GLabel prints a string. The thing is I have an int that I want to print there. How would I achieve this?

This is the loop I have, but this won’t compile because of the int there.

for( int k = 1; i> 5; k++){
    GLabel counter = new GLabel(k);
    add(counter, (getWidth() / 2), (getHeight() / 2) );
    pause (500);
    remove(counter);
}

When I try this: GLabel( (String)k); I get a “Cannot cast from int to String” error…

EDIT: I have seen the setLabel method-maybe that is the only way to do this?

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  1. Editorial Team
    Editorial Team
    2026-05-13T22:17:07+00:00Added an answer on May 13, 2026 at 10:17 pm

    Try GLabel("" + k); instead.

    You can’t cast an int to a String, so you have to do a conversion instead. There are various ways to do this, but an easy way is to just append it to an empty string.

    Other ways:

    • String.valueOf(k)
    • Integer.toString(k)
    • String.format("%d", k)

    One caveat with using the + string concatenation “trick” is that you need to take operator precedence into account.

    System.out.println("" + 1 + 2);   // this prints "12"
    System.out.println("" + (1 + 2)); // this prints "3"
    
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