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Home/ Questions/Q 1037143
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T14:49:07+00:00 2026-05-16T14:49:07+00:00

I’m learning linked lists, and want to know whether the following program (basically InsertAtEnd

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I’m learning linked lists, and want to know whether the following program (basically InsertAtEnd function) I’ve made for inserting elements at the end of the list is correct.

The basic idea is that *HEAD points to the first element of the list and *LAST points to the last element. This saves the time and calculations in traversing to the last element of the list and then adding elements.

#include<stdio.h>
#include<stdlib.h>

// Structure for the list element/node
struct node 
{
 int data; // Stores the data
 struct node *next; // Points to the next element in the list.
};

int InsertAtEnd(struct node **, struct node **, int); /*Declaration of the function which 
                                                    inserts elements at the end.*/

int main()
{
 struct node *HEAD=NULL; //Points to the first element in the list.
 struct node *LAST=NULL; //Points to the last element in the list.
 int i=1;

 for(i=1;i<11;i++)
   {
     InsertAtEnd(&HEAD,&LAST,i);
   }
 }

// Function to insert element at the end.
int InsertAtEnd(struct node **headref,struct node **lastref,int i)
 {
   struct node *newnode=malloc(sizeof(struct node)); /*Allocates memory for the newnode 
                                                     and store the address in pointer 
                                                     newnode*/
   newnode->data=i; // Assign value to the data variable of the newnode.
   newnode->next=NULL; // Assign NULL to the next pointer of the newnode.

   if(*headref==NULL) //Checks if the list is empty.
    {
      *headref=newnode; // Places the address of the new node in HEAD pointer.
      *lastref=newnode; // Places the address of the new node in LAST pointer.

       return 0; //Exit function
    }

/* If the list is not empty, then make the next pointer of the present last node point to the new node*/

   (*lastref)->next=newnode;

   *lastref=(*lastref)->next; // Increment LAST to point to the new last node.

    return 0;
}

The questions that I want to specifically ask are:

a) Is the above code for adding elements at the end (i.e InsertAtEnd function) correct? (Note: I tested it on my machine and it works as expected. But I still want to confirm from you people)

b)Is the code (InsertAtEnd function) efficient?

c)Will the efficiency of the code (InsertAtEnd function) be affected if I try to make a longer list.

d)Are there more efficient and simple algorithms to insert elements at the end? Can you direct me to them?

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  1. Editorial Team
    Editorial Team
    2026-05-16T14:49:07+00:00Added an answer on May 16, 2026 at 2:49 pm

    a) It seems correct

    b) It is. You could make the function return void, because you don’t need that int return value

    c) No. In other words the execution time is constant.

    d) malloc takes time. You could use a buffering technique, to malloc a chunk of nodes in advance and then take the next node from the buffer. When the buffer becomes empy, allocate another chunk. The chunk dimensions could be configured or even (complex) computed using statistical algorithms.

    Moreover, you don’t check for malloc’s NULL return, but it could fail.

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