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Home/ Questions/Q 8706281
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T03:34:37+00:00 2026-06-13T03:34:37+00:00

I’m learning objective-c from Programming in objective-c author Kochan. 3rd edition. In Chapter 8

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I’m learning objective-c from “Programming in objective-c” author Kochan. 3rd edition.
In Chapter 8 “Inheritance” Mr. Kochan gives following explanation to the method:

-(void) setOrigin: (XYPoint *) pt
{
if (! origin)
origin = [[XYPoint alloc] init];
origin.x = pt.x;
origin.y = pt.y;
}

“The method first tests to see if the instance variable origin is nonzero (make sure you
understand that test and the use of the logical negation operator ! that’s used). Recall that
all instance variables are initially set to zero. So when a new Rectangle object is allocated,
its instance variables, which includes origin, will be set to zero.

If the origin is zero, the setOrigin: method will allocate and initialize a new
XYPoint object and store the reference to it in the origin.”

Is there a logical mistake? Doesn’t the “setOrigin” method allocates a new XYPoint object only if the origin is non zero?

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  1. Editorial Team
    Editorial Team
    2026-06-13T03:34:38+00:00Added an answer on June 13, 2026 at 3:34 am

    The author is, indeed, correct.

    This is why I don’t like incomplete comparisons in C.

    If he codes if (origin) then that boolean expression is true for any value of origin which is non-zero.

    So, when he negates it, the boolean expression if (! origin) is true only when origin is zero.

    IMO, this is horrendous and should be coded if (origin == NULL) which makes it much clearer.

    It seems to me that he is going out of his way to teach bad coding habits. This sort of construct always gives off a Code Smell.

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