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Home/ Questions/Q 9045505
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T11:20:45+00:00 2026-06-16T11:20:45+00:00

I’m learning python from Google code class. I’m trying out the exercises. def front_x(words):

  • 0

I’m learning python from Google code class. I’m trying out the exercises.

def front_x(words):
  x_list, ord_list = []
  for word in words:
    if word[0] == 'x':
      x_list.append(word)
    else:
      ord_list.append(word)
  return sorted(x_list) + sorted(ord_list)      

I believe the error is thrown because of initializing two empty lists on a single line. If if initialize them on separate lines, no more errors occur. Is this the reason?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T11:20:49+00:00Added an answer on June 16, 2026 at 11:20 am

    You are trying to use tuple assignment:

    x_list, ord_list = []
    

    you probably meant to use multiple assignment:

    x_list = ord_list = []
    

    which will not do what you expect it to; use the following instead:

    x_list, ord_list = [], []
    

    or, best still:

    x_list = []
    ord_list = []
    

    When using a comma-separated list of variable names, Python expects there to be a sequence of expressions on the right-hand side that matches the number variables; the following would be legal too:

    two_lists = ([], [])
    x_list, ord_list = two_lists
    

    This is called tuple unpacking. If, on the other hand, you tried to use multiple assignment with one empty list literal (x_list = ord_list = []) then both x_list and ord_list would be pointing to the same list and any changes made through one variable will be visible on the other variable:

    >>> x_list = ord_list = []
    >>> x_list.append(1)
    >>> x_list
    [1]
    >>> ord_list
    [1]
    

    Better keep things crystal clear and use two separate assignments, giving each variable their own empty list.

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