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Home/ Questions/Q 6712893
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T08:18:52+00:00 2026-05-26T08:18:52+00:00

I’m learning Scala. I want to implement a subclass of Exception that gets a

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I’m learning Scala. I want to implement a subclass of Exception that gets a name as parameter and builds a message with that name embedded on it. Something similar to this:

class InvalidItem(itemName: String) extends Exception(msg: name) {
  def this(itemName)= {
    super("Invalid item: " + itemName)
  }
}

In this case, I simply want to prepend itemName with "Invalid item:" before passing it to the superconstructor. But I can’t find the way.

I’ve tried several similar syntaxes (i.e. replacing super by this) but kept getting cryptic errors.

What is the correct way of doing this in Scala?

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  1. Editorial Team
    Editorial Team
    2026-05-26T08:18:53+00:00Added an answer on May 26, 2026 at 8:18 am

    You’re actually calling the parent constructor in the extends clause, so the following works:

    class InvalidItem(itemName: String) extends Exception("Invalid item name" + itemName)
    

    For a discussion of this syntax and its motivation, see for example this blog post by Daniel Spiewak:

    That little bit of extra syntax in the extends clause is how you
    call to a superclass constructor… This may seem just a bit odd at
    first glance, but actually provides a nice syntactical way to ensure
    that the call to the super constructor is always the first statement
    in the constructor. In Java, this is of course compile-checked, but
    there’s nothing intuitively obvious in the syntax preventing you
    from calling to the super constructor farther down in the
    implementation. In Scala, calling the super constructor and calling a
    superclass method implementation are totally different operations,
    syntactically. This leads to a more intuitive flow in understanding
    why one can be invoked arbitrarily and the other must be called prior
    to anything else.

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