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Home/ Questions/Q 6653991
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T01:20:11+00:00 2026-05-26T01:20:11+00:00

I’m learning the basics of Ruby (just starting out), and I came across the

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I’m learning the basics of Ruby (just starting out), and I came across the Hash.[] method. It was introduced with

a = ["foo", 1, "bar", 2]
=> ["foo", 1, "bar", 2]
Hash[*a]
=> {"foo"=>1, "bar"=>2}

With a little thought, I figured out that Hash[*a] is equivalent to Hash.[](*a) or Hash.[] *a. My question is why that’s the case. What is it that lets you put the *a inside the square brackets, and is there some kind of rule for where and when else “it” can be used?

Edit: My wording seems to be causing some confusion. I’m not asking about the array expansion. I get that. My question is basically: if [] is a method name, why is it okay to put arguments inside the brackets? It seems almost–but not quite–like saying that if you have a method Foo.dood, and you wanted to pass the string "hey" to it, then you could write Foo.do"hey"od.

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  1. Editorial Team
    Editorial Team
    2026-05-26T01:20:12+00:00Added an answer on May 26, 2026 at 1:20 am

    There are a couple methods that ruby lets you call in a special way. These are the [] as you mentioned, the +, -, == and the like as someone else mentioned. Another important example are methods of the form something=(value) which can be called with object.something = value and allow you to create accessors.

    Edit:

    Fun fact 1: if you define a + method you get += for free.

    Fun fact 2: if you define a <=> you get all comparison methods, courtesy of Comparable

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