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Home/ Questions/Q 9066837
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T16:48:24+00:00 2026-06-16T16:48:24+00:00

I’m looking for a function (hopefully built in) that can create fixed width strings

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I’m looking for a function (hopefully built in) that can create fixed width strings of certian padding and alignments. In my case I have a list of names (among other data) that needs to get put into a fixed with format file.

Example 1: "Spams spam and spam" and "viking inc" both need to be placed into a 15 character fixed width field.
Result: ("Spams spam and ", "viking inc ")

Example 2: A numeric version that converts (25, 100, 1234567890) into an 8 character fixed width string padded with zeros.
Result: ("00000025", "00000100" "34567890") <- Note how dropped the first 2 chars

Acceptable answers may also include calling me an idiot and telling me that there’s something simple for fixed width string handling. Also this should ideally work in python 2.7 and 3.3 (our company is currently on 2.7, but will move to 3.3 soon)

What I’ve tried:

"{0:<30}".format("viking inc")  #works
"{0:<30}".format("Spams spam and spam") #does not work, output it too long.
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  1. Editorial Team
    Editorial Team
    2026-06-16T16:48:25+00:00Added an answer on June 16, 2026 at 4:48 pm

    For the numbers:

    >>> for n in (25, 100, 1234567890):
            print('{:0>8}'.format(n)[-8:])
    
    00000025
    00000100
    34567890
    

    For the strings, your example is a bit ambigous. If you want to select just the first 15 characters (at most), then just do this:

    >>> 'Spams spam and spam'[:15]
    'Spams spam and '
    >>> 'viking inc'[:15]
    'viking inc'
    

    If you want to pad it again—which you didn’t in your example—then you can use format again:

    >>> '{:<15}'.format('Spams spam and spam'[:15])
    'Spams spam and '
    >>> '{:<15}'.format('viking inc'[:15])
    'viking inc     '
    
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