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Home/ Questions/Q 998635
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T07:13:41+00:00 2026-05-16T07:13:41+00:00

I’m looking for a nice clean routine for turning an NSArray containing NSNumbers (integers)

  • 0

I’m looking for a nice clean routine for turning an NSArray containing NSNumbers (integers) into a nice English-readable string. For example, I want to change this:

[NSArray arrayWithObjects:[NSNumber numberWithInt:5],
                          [NSNumber numberWithInt:7],
                          [NSNumber numberWithInt:12],
                          [NSNumber numberWithInt:33], nil];

into this:

5, 7, 12 and 13.

Is there any nice way of doing this without hideous if statement logic? I’m sure it can be done with a regular expression, but is that possible in pre-iOS 4 code?

Thanks! 🙂

:-Joe

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T07:13:42+00:00Added an answer on May 16, 2026 at 7:13 am

    Look mom, no ifs!

    NSString *seps[] = {@" and ",@"",@", ",nil,nil,@", "}, *o = @".", *sep = o;
    for ( NSNumber *n in [arr reverseObjectEnumerator] ) {
       o = [NSString stringWithFormat:@"%@%@%@",n,sep = seps[[sep length]],o];
    }
    
    NSLog(@"out: %@",o);
    

    output:

    out: 5, 7, 12 and 33.
    

    but why?

    edit here is an understandable version with no “huge if/else construct”

    NSString *out = @"";  // no numbers = empty string
    NSString *sep = @"."; // the separator first used is actually the ending "."
    for ( NSNumber *n in [arr reverseObjectEnumerator] )
    {
        out = [NSString stringWithFormat:@"%@%@%@",n,sep,out];
        if ( [sep isEqualToString:@"."] ) // was the separator the ending "." ?
        {
            sep = @" and "; // if so, put in the last separator " and "
        } else {
            sep = @", ";    // otherwise, use separator ", "
        }
    }
    

    This will output strings like

    0 elements: ""        (i.e. empty)
    1 element:  "33."
    2 elements: "12 and 33."
    3 elements: "7, 12 and 33."
    
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