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Home/ Questions/Q 6981759
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T18:11:56+00:00 2026-05-27T18:11:56+00:00

I’m looking for a way to do this: qs = MyModel.objects.filter(mystring__like=____10____) #Which would create

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I’m looking for a way to do this:

qs = MyModel.objects.filter(mystring__like="____10____")

#Which would create a sql clause
... LIKE '____10____'

instead of behave like this:

qs = MyModel.objects.filter(mystring__icontains="____10____")
#Which creates a sql clause
... LIKE %\_\\_\\_\\_10\\_\\_\\_\\_%

I know I can use a regex filter, but that’s substantially slower and more error prone than just using the built-in mysql wildcard feature (I’ve tested it directly in mysql, the query strings are long enough that the difference is substantial).


EDIT:
figured out how to do this with the .extra() method with madisvain’s help.

qs = MyModel.objects.extra(where=["`mystring` LIKE '____10____'"])

In terms of performance difference, 2000 random queries with the regex approach took 20.5 seconds, with this approach 2000 random queries take 6 seconds.

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  1. Editorial Team
    Editorial Team
    2026-05-27T18:11:56+00:00Added an answer on May 27, 2026 at 6:11 pm

    I didn’t even know django had this __like version. Well but according to the docs please read this!
    https://docs.djangoproject.com/en/dev/topics/db/queries/#escaping-percent-signs-and-underscores-in-like-statements

    You should be writing the query like this.

        qs = MyModel.objects.filter(mystring__contains="____10____")
    

    Or this.

        qs = MyModel.objects.extra(where="mystring LIKE '____10____'")
    

    Read more about the extra() method here:
    https://docs.djangoproject.com/en/dev/ref/models/querysets/#extra

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