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Home/ Questions/Q 6548265
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T11:55:51+00:00 2026-05-25T11:55:51+00:00

I’m looking for a way to match a C identifier followed by a double-underscore.

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I’m looking for a way to match a C identifier followed by a double-underscore. But here’s the thing: I need it to be non-greedy if the identifier ends in a series of underscores.

I almost got it with ^([_A-Za-z][_A-Za-z0-9]*?)__ but there’s a tricky set of cases where the identifier can end in a series of underscores:

string          expected identifier
abcd0__         abcd0
abcd0___        abcd0_
abcd0____       abcd0__
abcd__0__       abcd
abcd___0__      abcd_
abcd____0__     abcd__

Is there a way I can modify the regex to produce the expected group match listed above?

Below is a test program which prints the incorrect output:

abcd0__ -> match is abcd0
abcd0___ -> match is abcd0
abcd0____ -> match is abcd0
abcd__0__ -> match is abcd
abcd___0__ -> match is abcd
abcd____0__ -> match is abcd

Regex3.java:

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Regex3 {
    final static private Pattern pattern = 
       Pattern.compile("^([_A-Za-z][_A-Za-z0-9]*?)__");

    static public void main(String[] args)
    {
        String[] items = {
                "abcd0__",
                "abcd0___",
                "abcd0____",
                "abcd__0__",
                "abcd___0__"
                "abcd____0__"
        };
        for (String item : items)
            test(item);
    }
    private static void test(String item) {
        Matcher m = pattern.matcher(item);
        if (m.find())
        {
            System.out.println(item+" -> match is "+m.group(1));
        }
        else
        {
            System.out.println(item+" -> no match");            
        }
    }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T11:55:52+00:00Added an answer on May 25, 2026 at 11:55 am

    ^[_A-Za-z](?:_?[A-Za-z0-9])*_*(?=__)

    In JavaScript in the squarefree shell,

    var re = /^[_A-Za-z](?:_?[A-Za-z0-9])*_*(?=__)/
    var arr = ["abcd0__", "abcd0___", "abcd0____", "abcd__0__", "abcd___0__",
               "abcd____0__", "abcd", "abcd_"]
    for (var i = 0; i < arr.length; i++) {
      print(arr[i] + " : " + re.exec(arr[i]));
    }
    

    produces

    abcd0__ : abcd0
    abcd0___ : abcd0_
    abcd0____ : abcd0__
    abcd__0__ : abcd
    abcd___0__ : abcd_
    abcd____0__ : abcd__
    abcd : null
    abcd_ : null
    
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