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Home/ Questions/Q 7894145
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T07:19:09+00:00 2026-06-03T07:19:09+00:00

I’m looking for a way to reduce this list to a boolean. Here is

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I’m looking for a way to reduce this list to a boolean. Here is the original:

let ones = [1;1;1;1]
let twos = [2;2;2;2]
let bad = [1;2;3]

let isAllOnes = List.forall (fun op -> op = 1)
let isAllTwos = List.forall (fun op -> op = 2)  

let isOneOrTwo ops = isAllOnes ops || isAllTwos ops

isOneOrTwo ones |> should be True
isOneOrTwo twos |> should be True
isOneOrTwo bad |> should be False

I’m trying to refactor this using a kind of reduce. Something like this:

let isOneOrTwo ops = [isAllOnes; isAllTwos] |> List.tryFind (fun acc -> acc ops) 

(isOneOrTwo ones).IsSome |> should be True
(isOneOrTwo twos).IsSome |> should be True
(isOneOrTwo bad).IsSome |> should be False

I don’t like how isOneOrTwo reduces to an Option. I really would like to reduce the list to a boolean so that my assertions can look like this:

isOneOrTwo ones |> should be True
isOneOrTwo twos |> should be True
isOneOrTwo bad |> should be False

Anyone know how to make this happen? List.reduce didn’t work because the types were different.

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  1. Editorial Team
    Editorial Team
    2026-06-03T07:19:10+00:00Added an answer on June 3, 2026 at 7:19 am

    Replace List.tryFind with List.exists

    let ones = [1;1;1;1]
    let twos = [2;2;2;2]
    let bad = [1;2;3]
    
    let allOnes = List.forall ((=) 1)
    let allTwos = List.forall ((=) 2)
    
    let isOneOrTwo l = [allOnes; allTwos] |> List.exists (fun f -> f l)
    
    printfn "%A " (isOneOrTwo ones) // true
    printfn "%A " (isOneOrTwo twos) // true
    printfn "%A " (isOneOrTwo bad)  // false
    
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