Question

I’m looking for the best approach to my problem.

I need to display the names only of 3 different entities, not the rest of the information.

Entities are:

db.TR{TRID, ProjectID, TemplateID, version}
db.Project{ProjectID, ProjectName}
db.Template{TemplateID, TemplateName}

I would like the best approach to display all the results in a grid like this:

TRID - ProjectName - TemplateName - Version

I would like to know how you would do the Model, Controller(Index Function) and the view.

So far, my View function looks like this:

public ViewResult Index()  
{  
    var viewModel = from tr in db.TRs   
    join proj in db.Projects on tr.ProjectID equals proj.ProjectID   
    join templ in db.Templates on tr.TemplateID equals templ.TemplateID  
    orderby proj.ProjectName  
    select new  
    {  
        TRList = tr.TRID,  
        TemplateList = templ.TemplateName,  
        ProjectList = proj.ProjectName,  
        Version = tr.version  
    }   
    return View(viewModel); //Go in Index.cshtml  
}

And the View is:

@model IEnumerable <OnlineTR.WebUI.Areas.Admin.Models.TRManagerModel>  
@foreach (var item in Model)  
             {
            <tr>  
                <td>  
                   @Html.DisplayFor(modelitem => item.TRList);  
                </td>  
                <td>  
                   @Html.DisplayFor(modelitem => item.ProjectList);  
                </td>  
                <td>  
                   @Html.DisplayFor(modelitem => item.TemplateList);  
                </td>  
            </tr>  
            }

I’m trying to find a way to use a sql request that only use what I need.

If you can show me how to use the .include, it would be awesome. So far I have try, but it doesn’t accept lambda expressions in the (), it wants a string path. (maybe missing a using?)

Thanks a lot. Alex.

Answer 1

The problem with your code is that you are passing IEnumerable of anonymous type to your view, but it expects the type

@model IEnumerable <OnlineTR.WebUI.Areas.Admin.Models.TRManagerModel>

Fix your LINQ query to select a concrete type, and it will work

select new TRManagerModel
    {  
        TRList = tr.TRID,  
        TemplateList = templ.TemplateName,  
        ProjectList = proj.ProjectName,  
        Version = tr.version  
    }