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Home/ Questions/Q 6161835
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T21:32:47+00:00 2026-05-23T21:32:47+00:00

I’m looking specifically for a regular expression that will grab the last term of

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I’m looking specifically for a regular expression that will grab the last term of a URL. This is not always a file name, it may not end in .html or .php, so I’ll need to make sure that the regular expression is grabbing the last term from the URL.


Example:

I need to grab http://www.mydomain.com/anything_can_be_here/thankyoupage

I need to extract “thankyoupage” even when there can be any term preceding it in the URL.

Also note, there is no file extension on the thankyoupage URL segment.

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  1. Editorial Team
    Editorial Team
    2026-05-23T21:32:48+00:00Added an answer on May 23, 2026 at 9:32 pm

    This should do it:

    /^(?:http:\/\/)?(?:[^\/]+)\/.*?\/([^\/]+)(?:\?.*)?$/
    

    For example, the result of this:

    m = 'http://example.com/where/is?the=pancakes/house'.match(/^(?:http:\/\/)?(?:[^\/]+)\/.*?\/([^\/]+)(?:\?.*)?$/);
    

    is this array:

    ["http://example.com/where/is?the=pancakes/house", "is"]
    

    And this:

    m = 'http://example.com/where/is'.match(/^(?:http:\/\/)?(?:[^\/]+)\/.*?\/([^\/]+)(?:\?.*)?$/)
    

    Results in:

    ["http://example.com/where/is", "is"]
    

    And this:

    m = 'http://example.com/'.match(/^(?:http:\/\/)?(?:[^\/]+)\/.*?\/([^\/]+)(?:\?.*)?$/)
    

    Results in null.

    And your component is in m[1] and that comes from ([^\/]+). The (?:[^\/]+) will take care of the hostname (and the userinfo if it happens to be present), the (?:\?.*)?$ part will take care of any trailing CGI arguments.

    Depending on your URLs, you could replace ^(?:http:\/\/)? with ^http:\/\/.

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