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Editorial Team
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Asked: 2026-05-24T15:56:45+00:00

I’m looking to build a SQL query something like: SELECT email.member_id, 1 FROM email

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I’m looking to build a SQL query something like:

"SELECT email.member_id, 1 FROM email ... "

I’m using

$this->Email->find('list', array(
  'fields' => array('Email.member_id', '1'), ...

CakePHP is generating:

SELECT `Email`.`member_id`, `Email`.`1` FROM `emails` AS `Email` ...

How do I specify that the 1 is a constant and not a database field?

Why I want to do this

I basically want to return an associative array with keys of member_id and values of 1. Would it be better to just get a straight array of member_ids and then transform that into my wanted data structure? I thought this would be faster.

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1 Answer

  1. Editorial Team

    Cake does not easily allow that. In your specific case I would be wondering why you want to have a constant field anyways. But in general do to stuff like that you are supposed to use Virtual Fields:

    http://book.cakephp.org/view/1608/Virtual-fields

    Basically you would modify model Email by adding this:

    var $virtualFields = array(
   'one' => '1'
);

    Now you can do your query like this:

    $this->Email->find('list', array(
  'fields' => array('Email.member_id', 'Email.one'), ...

    For the usecase you added you should just get a straight array of ids and fill it afterwards. Not only will be that faster, but also less hacky => easier to understand. You can do that easily with ´array_fill_keys()´.

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