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Home/ Questions/Q 7018833
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T23:06:12+00:00 2026-05-27T23:06:12+00:00

I’m looking to do something like the following: class Whatever { public: enum PhysicalObjectType

  • 0

I’m looking to do something like the following:

class Whatever {
public:

    enum PhysicalObjectType {
            STATIC_MISC_OBJECT,
            DYNAMIC_MISC_OBJECT,
            STATIC_MISC_OBJECT_WALKABLE,
            DYNAMIC_MISC_OBJECT_WALKABLE,
            STATIC_MISC_OBJECT_KILL,
            DYNAMIC_MISC_OBJECT_KILL,
            STATIC_MISC_OBJECT_BREAK,
            DYNAMIC_MISC_OBJECT_BREAK,
            BOUNDARY,
            BOUNDARY_GROUND,
            PERMANENT_JOINT,
            MOUSE_JOINT
    };
};

And then a method that will retrieve a type based on the above code outside of the class. So lets say within another class I have an instance of Whatever and I call getType() on myWhateverInstance and do a comparison to determine what type it is, like so:

if( myWhateverInstance.getType() == STATIC_MISC_OBJECT ) {

}else ...

That however, is not working. Basically no matter how I try and resolve them, I cannot access any values within the enum outside of the class. What noob mistake am I making here? (Note the specific errors I’m getting are not declared in scope or XX is not a valid namespace or class, etc).

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T23:06:13+00:00Added an answer on May 27, 2026 at 11:06 pm

    When accessing enumerators that are members of a class, you have to qualify their names with the class’s name. So the enumerators are Whatever::STATIC_MISC_OBJECT and so forth.

    This is only necessary when accessing the enumerator from outside of the class. From within the class’s scope, you can simply use the base name.

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