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Editorial Team
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Asked: 2026-05-23T01:38:34+00:00

I’m looking to simply pull some quoted text out of a function call and

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I’m looking to simply pull some quoted text out of a function call and was wondering if I could get some help with regex?

The string would look something like this:
‘MyFunction(“MyStringArg”);’

I would, essentially, like to scan a file for any lines that call ‘MyFunction’, and then capture the string literal within the quotes.

Follow-up Question
How would I go about avoiding commented lines with this?

Update
I was able to solve my problem with:
MyFunction\s*\(\s*"(.*?)\"\s*\)\s*;

Thanks @devyndraen and everyone for your help!

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1 Answer

  1. Editorial Team

    I’m not sure what kinds of requirements for formatting you have, so I included the assumption that there could be any amount of space in the normal programming places there could be some.

    The resultant string will be in the \1 backreference.

    MyFunction\s*\(\s*"(.*?)\"\s*\)\s*;

    http://rubular.com/r/qVsaqJS6gJ

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