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Home/ Questions/Q 6061415
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T08:56:07+00:00 2026-05-23T08:56:07+00:00

I’m looking to simulate a poset, called x say, of size 2n in java

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I’m looking to simulate a poset, called x say, of size 2n in java of the form a_1 < a_2 < … < a_n, and b_1 < b_2 < … < b_n.

I want to run an iteration to get a random linear extension whereby I compare the ‘size’ of each object and if two adjacent positions can be switched I do so, if not then I stick, to end with a new order. For example x[i] = a_k and x[i+1] = b_k I switch them, however if x[i] = a_k and x[i+1] = a_(k+1) I would not. (In essence this is the Karzanov Khachiyan chain).

I initially thought of using an array of arrays where x[][] = {a_1[], …, b_1[], … }, where say a_1 = {a,1}, where I could compare the values and easily make a switch. Now I am trying to think of other ways to do this, as from my previous quesiton I can see this isn’t going to be a partiularly efficient or elegant way of doing this. Does anyone have any suggestions?

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  1. Editorial Team
    Editorial Team
    2026-05-23T08:56:07+00:00Added an answer on May 23, 2026 at 8:56 am

    Well first, I like your idea of storing the whole chain in an array. I think that will work fine.

    But I agree with you that the “nested” array,

    { {'a', 1}, {'a', 2}, ... }
    

    will probably be a little annoying. Have you thought of making a class like

    class Elem {
        String symbol;
        int subscript;
    }
    

    You could then write a comparator to say whether one Elem is less than another:

    Comparator<Elem> comp = new Comparator<Elem>() {
        public int compareTo(Elem e1, Elem e2) {
            // return -1 if e1<e2, +1 if e2<e1, 0 otherwise
        }
        public boolean equals(Elem e1, Elem e2) {
            // ...
        }
    };
    

    I think that might make your life easier because then one element feels more like a single object.

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