Question

I’m looking to write a script that will load up a file that has a bunch of directory/filenames in CSV format, and then output what files are not found.

This is what I have so far:

for /f "delims=, tokens=1,2,3" %i in (C:\foo.csv) do dir "Y:\%i\%j\%k" >> C:\temp\log.txt

Which outputs everything.

What I really want is for it to log nothing if it is found, and then just a single line error of something similar to:

File AC\0d\234csf-234wfv-423vx-23fsdfs.jpg was not found

But right now it logs everything.

How can I achieve this?

Answer 1

You seem to use the command interactively so here’s a solution to be used directly in the console:

for /f "delims=, tokens=1,2,3" %i in (C:\foo.csv) do dir "Y:\%i\%j\%k" >nul 2>nul || echo File "Y:\%i\%j\%k" was not found>> C:\temp\log.txt

A more readable multi-line version (to be used in a batch script, obviously, hence %% instead of %):

for /f "delims=, tokens=1,2,3" %%i in (C:\foo.csv) do (
dir "Y:\%%i\%%j\%%k" >nul 2>nul || echo File "Y:\%%i\%%j\%%k" was not found>> C:\temp\log.txt
)