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Home/ Questions/Q 8832273
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T08:29:29+00:00 2026-06-14T08:29:29+00:00

I’m looping through each relevant tag in an XML file and executing this code.

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I’m looping through each relevant tag in an XML file and executing this code.

$('<div class="product_image"></div>').html('<a href="'+url+'"><img src='+urlZoomImage+' /></a>').appendTo('#content');
$('<div class="product_title"></div>').html('<a href="'+url+'">'+title+'</a>').appendTo('#content');

I want to surround product_image and product_title with a div called product_box like this:

<div id="content">
  <div class="product_box">
    <div class="product_image">My image code</div>
    <div class="product_title">My title code</div>
  </div>
</div>

Only the content div is written in the HTML and it must remain like this (I can’t write the product_box code in there as it is to be generated on each successful find). How do I do this?

Thanks in advance.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T08:29:31+00:00Added an answer on June 14, 2026 at 8:29 am

    You can easily get lost in code, when you use jQuery for creating HTML elements. Try to save the seperate elements in variables and arrange them after initialising.
    Like this:

    var div_box = $('<div></div>').addClass('product_box');
    var div_image = $('<div></div>').addClass('product_image').html('<a href="'+url+'"><img src='+urlZoomImage+' /></a>');
    var div_title = $('<div></div>').addClass('product_title').html('<a href="'+url+'">'+title+'</a>');
    $('#content').append(div_box.append(div_image).append(div_title));
    
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