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Home/ Questions/Q 9022637
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T05:33:50+00:00 2026-06-16T05:33:50+00:00

I’m making a Client-Server. I’ve gotten as far as that the server can send

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I’m making a Client-Server. I’ve gotten as far as that the server can send a hardcoded file, but not a client specified. I will have to send only text files. As far as I have understood: the clients firstly sends the file name and then, the server sends it, nothing complicated, but I’m getting all kinds of errors, this code is getting a connection reset/socket closed error. The main problem is, that hadn’t got much time to research networking.

Ill appreciate any help I can get.

EDIT.
I found a work around, closing a stream causes the socket to close, why is that? It shouldn’t happen, should it?

Server Side:

    InputStream sin=newCon.getInputStream();
    DataInputStream sdata=new DataInputStream(sin);
    location=sdata.readUTF();   
    //sdata.close();
    //sin.close();

File toSend=new File(location);
byte[] array=new byte[(int)toSend.length()];
FileInputStream fromFile=new FileInputStream(toSend);
BufferedInputStream toBuffer=new BufferedInputStream(fromFile);
toBuffer.read(array,0,array.length);

OutputStream out=newCon.getOutputStream(); //Socket-closed...
out.write(array,0,array.length);
out.flush();
toBuffer.close();
newCon.close();

ClientSide:

int bytesRead;
server=new Socket(host,port);

OutputStream sout=server.getOutputStream();
DataOutputStream sdata=new DataOutputStream(sout);
sdata.writeUTF(interestFile);
//sdata.close();
//sout.close();

InputStream in=server.getInputStream();     //socket closed..
OutputStream out=new FileOutputStream("data.txt");
byte[] buffer=new byte[1024];
while((bytesRead=in.read(buffer))!=-1)
{
    out.write(buffer,0,bytesRead);
}
out.close();
server.close();
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T05:33:51+00:00Added an answer on June 16, 2026 at 5:33 am

    Try reading the file in chunks from Server while writing to client output stream rather than creating a temp byte array and reading entire file into memory. What if requested file is large? Also close the new Socket on server-side in a finally block so socket is closed even if an exception is thrown.

    Server Side:

        Socket newCon = ss.accept();
        FileInputStream is = null;
        OutputStream out = null;
        try {
            InputStream sin = newCon.getInputStream();
            DataInputStream sdata = new DataInputStream(sin);
            String location = sdata.readUTF();
            System.out.println("location=" + location);
            File toSend = new File(location);
            // TODO: validate file is safe to access here
            if (!toSend.exists()) {
                System.out.println("File does not exist");
                return;
            }
            is = new FileInputStream(toSend);
            out = newCon.getOutputStream();
            int bytesRead;
            byte[] buffer = new byte[4096];
            while ((bytesRead = is.read(buffer)) != -1) {
                out.write(buffer, 0, bytesRead);
            }
            out.flush();
        } finally {
            if (out != null)
                try {
                   out.close();
                } catch(IOException e) {
                }
            if (is != null)
                try {
                   is.close();
                } catch(IOException e) {
                }
            newCon.close();
        }
    

    If you use Apache Common IOUtils library then you can reduce much of the code to read/write files to streams. Here 5-lines down to one line.

    org.apache.commons.io.IOUtils.copy(is, out);
    

    Note that having a server that serves files by absolute path to remote clients is potentially dangerous and the target file should be restricted to a given directory and/or set of file types. Don’t want to serve out system-level files to unauthenticated clients.

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