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Home/ Questions/Q 6985555
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T18:41:43+00:00 2026-05-27T18:41:43+00:00

I’m making a method that load a graph from a file. It’s very simple,

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I’m making a method that load a graph from a file. It’s very simple, but if there are repeated vertex, the method’ll insert too into the graph, so I’m trying to avoid this.

This is my current code:

public static Graph<ElementoDecorado<Integer>, String> loadGraphFromFile(File f) {
        boolean v1_exists = false, v2_exists = false;
        Graph<ElementoDecorado<Integer>, String> g = new AdjacencyListGraph<ElementoDecorado<Integer>, String>();
        Vertex<ElementoDecorado<Integer>> v1, v2, aux = null;
        Scanner fr;

        try {
            fr = new Scanner(f);

            while(fr.hasNextLine()) {
                v1 = g.insertVertex(new ElementoDecorado<Integer>(fr.nextInt()));
                v2 = g.insertVertex(new ElementoDecorado<Integer>(fr.nextInt()));

                for(Vertex<ElementoDecorado<Integer>> v : g.vertices()) {
                    if(v.equals(v1)) {

                        /*aux = v;
                        v1_exists = true;*/
                    }
                    if(v.equals(v2)) {
                        /*aux = v;
                        v2_exists = true;*/
                    }
                }

                g.insertEdge(v1, v2, "edge");

                v1_exists = v2_exists = false;
            }
        } catch(FileNotFoundException e) {
            e.printStackTrace();
        }

        return g;
    }

I don’t know what to write into the two ifs. I have tried to delete the vertex if they are equal but obviously this doesn’t work cause at the end my graph’ll be empty :S

This is the manual page for the Vertex interface.

Any help is welcome.
Thanks, and merry christmas!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T18:41:44+00:00Added an answer on May 27, 2026 at 6:41 pm

    You should first check what graph.insertVertex(V value) does. If the package was build decently (which I doubt from the poor documentation), then that method will only create a new vertex if a vertex with value does not already exist; otherwise it returns the existing vertex of value value.

    However I can’t tell from the non-documentation whether the package really assumes that there is a single vertex for a given value and whether insertVertex behaves correctly.

    Here is some code in case insertVertex does not check for duplication:

    (I replaced ElementoDecorado<Integer> by Integer for readability)

    while(fr.hasNextLine()) {
       int nodeId1 = fr.nextInt();
       int nodeId2 = fr.nextInt();
       Vertex<Integer> vert1 = null;
       Vertex<Integer> vert2 = null;
    
       for(Vertex<Integer> v : g.vertices()) {
          int nodeId = v.element();
          if(nodeId == nodeId1) 
             vert1 = v;
          else if (nodeId == nodeId2) // assumes can't have nodeId1 == nodeId2
             vert2 = v;
        }
        if (vert1 == null)
           vert1 = g.insertVertex(nodeId1);
        if (vert2 == null)
           vert2 = g.insertVertex(nodeId2);
    
        g.insertEdge(vert1, vert2, null);
     }
    
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