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Home/ Questions/Q 6797427
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T18:36:29+00:00 2026-05-26T18:36:29+00:00

I’m making a simple lightbox. If you click on an image, it takes that

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I’m making a simple lightbox. If you click on an image, it takes that image and shows it full screen with a black background behind it.

Here is my code:

$('.theContent img').live('click', function(e) {
    var lbImg = $(this);
    $('#lb').toggle();
    $('#lb').find("#lbImg").append(lbImg);           

)

Thing is, it takes away the variable lbImg and puts it in the lightbox. I dont want that, i just want to copy that bit of info and duplicate, rather than reposition. How would you go about that?

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  1. Editorial Team
    Editorial Team
    2026-05-26T18:36:30+00:00Added an answer on May 26, 2026 at 6:36 pm

    Use the .clone() method to copy the element:

    var lbImg = $(this).clone();
    

    Normally, when an element is re-appended, it is removed from the previous location. When an element have to be appended without removing it from the previous spot, it has to be duplicated.

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