Question

I’m making an image sharing website with php. I was reading about google’s pagespeed, and they said I needed to optimize my images, so I’ve been trying to do that with imagejpeg, then hopefully I’ll be able to use basically the same code with png and gif.

This is the code I have at the moment:

$img = imagecreatefromjpeg($original);

if ($extension === "jpg" || $extension === "jpeg"){
    $location = $_SERVER['DOCUMENT_ROOT'] . "/uploads/" . $id . "/fullsize." . $extension;
    $temp = fopen($location, 'w');
    imagejpeg($img, $location, 80);
    fclose($temp);
}

And it does the job of taking the image at $original, and saving a copy that’s been through imagejpeg to $location.

But sometimes the resulting file is larger than the original was! This is where I get stumped.

Why is this happening?

How can I make it stop happening?

I’m trying to reduce image file sizes without hurting their appearance, is there a better way to do it than this?

Thanks,

Liam

Answer 1

imagejpeg will only shrink the file if you save it at a lower quality setting than the original was produced with

e.g.

imagejpeg($gd, 'temp.jpg', 50);
$temp = imagecreatefromjpeg('temp.jpg');
imagejpeg($gd, 'temp2.jpg', 70);

will probably produce a larger temp2 file, because it’s at a higher quality setting, which roughly translates to “don’t compress as much”.

There’s no way to predict what the final output size will be for a given image and quality setting without actually going through the whole jpeg compress process. You may have to do a few trial recompresses of an image and lower the quality setting each time until you start getting some shrinkage.

of course, if you lower the quality TOO low, you’ll basically trash the image and definitely introduce visible artifacts.