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Home/ Questions/Q 6184015
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T01:27:50+00:00 2026-05-24T01:27:50+00:00

I’m making my own function for the first time $.fn.testing = function(){….} ; But

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I’m making my own function for the first time $.fn.testing = function(){....};

But i’m having a problem that I’m not able to solve yet. The next scenario isn’t smart, but It might happen, so that’s the reason why I want to fix it so the user doesn’t have to:

$('.target').testing("message" : "Hello!");
$('#test .target').testing("message" : "Hello world!");

The function will make the ‘message’ pop-up. So what the user wants here is that, for every .target there has to be an pop-upbox with “Hello!” and if this .target also has an id of #test then it should pop-up: “Hello world!”. But the problem is, that now the script will pop-up “Hello!” AND “Hello world!” when the .target#test is triggered.

So what I want in my function is that the function sees if the function is already called on this object, and if it is it has to .unbind() the previous function and then continues to add the function.

How can I achieve this? Hopefully my explanation is clear enough!

(The example above is a little bit simplified, so please don’t comment on the use of it)

Help is appreciated!

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  1. Editorial Team
    Editorial Team
    2026-05-24T01:27:51+00:00Added an answer on May 24, 2026 at 1:27 am

    Here is how I would do this:

    var _myFunction = function() {
      alert($(this).data("message"));
    };
    

    in plugin do something like this

    jQuery.fn.testing = function(msg) {
        this
            .data("message", msg)
            .unbind('click', _myFunction)
            .bind('click', _myFunction);
    };
    

    EDIT: here is an example in jsfiddle

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