Question

im making some application form in PHP.

im putting all info returned from the database into a table.

Now i want to create a button on each line that changes something in the DB of that line.

but i have no idea to do that :S

Thank you!

echo "<table border='1'>
<tr>
<th>Id</th>
<th>Name</th>
<th>Email</th>
<th>age</th>
<th>position</th>
<th>experience</th>
<th>motivation</th>
<th>date</th>
<th>status</th>
<th>test</th>
</tr>";

while($row = mysql_fetch_array($result))
    {
        echo "<tr>";
    echo "<td>" . $row['id'] . "</td>";
    echo "<td>" . $row['name'] . "</td>";
    echo "<td>" . $row['email'] . "</td>";
    echo "<td>" . $row['age'] . "</td>";
    echo "<td>" . $row['position'] . "</td>";
    echo "<td>" . $row['exp'] . "</td>";
    echo "<td>" . $row['motivation'] . "</td>";
    echo "<td>" . $row['date'] . "</td>";
    echo "<td>" . $row['status'] . "</td>";
    echo "<td>" . '<input type="submit" name="submit" value="accept">' . "</td>";
    echo "</tr>";

}
    echo "</table>";

EDIT: get it working using another script:

echo "<td><a href=\"edit.php?id=".$row['id']."&status=app\">Approve</a></td>";

and edit.php:

<?php
include("dbconnect.php");
$member_id = $_GET['id'];
$status = $_GET['status'];
echo $member_id;
echo $status;
if ($status == 'app')
    $query = "update apps set status = 'approved' where id = $member_id";
mysql_query($query) or die (mysql_error());  
?>

Answer 1

Create small form with parameters in the cell you want the button to do smth. This is the simpliest approach (approach with refresh).

One more solution is to use AJAX on button click and forward action to some endpoint. This way it would be dynamic and probably what you are want to implement.