Question

I’m new in JS, and having quite hard time reading the following JS code.

The first parameter of the function is a url to a PHP script, the second is a string.

What confuses me is how to read code after the line:
self.xmlHttpReq.open(‘POST’, strURL, true);

What happens after this? Which code should i look after this line? The script?
What happens after open?

function check_detail(strURL, pids) 
{
    var xmlHttpReq = false;
    var self = this;
    // Mozilla/Safari
    if (window.XMLHttpRequest) {
        self.xmlHttpReq = new XMLHttpRequest();
    }
    // IE
    else if (window.ActiveXObject) {
        self.xmlHttpReq = new ActiveXObject("Microsoft.XMLHTTP");
    }
    self.xmlHttpReq.open('POST', strURL, true);
    self.xmlHttpReq.setRequestHeader('Content-Type', 'application/x-www-form-urlencoded');
    self.xmlHttpReq.onreadystatechange = function() 
    {
        if (self.xmlHttpReq.readyState == 4)
            updatepage(self.xmlHttpReq.responseText, pids);
    }
    self.xmlHttpReq.send(getquery(pids));
}

Answer 1

When you make an Ajax request (which is what you are doing here) it is asynchronous, which means that you don’t know exactly when it will return so you can’t just wait for the return.

Instead, you set up your function so that, when the request returns, a function is kicked off to handle the response. This is the onreadystatechange piece.

So the chronology will be: first the send() will occur, which will send the result of the getquery() method up to the PHP page. When that returns, the function defined within onreadystatechange will fire, which will call updatepage() and pass it both the text that was sent back from the Ajax call, and also the pids parameter.