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Home/ Questions/Q 6652065
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T01:05:19+00:00 2026-05-26T01:05:19+00:00

I’m new in PHP and I think this is an easy question. I can

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I’m new in PHP and I think this is an easy question.

I can show the content that comes from my db this way:

...
...
 <?php while($rows = mysql_fetch_array($queryNews)){    ?>
  <div class='title_news'><?php echo $row['Title'] ?> </div>
.... and so on... 

Thats ok so far

Then I want to simulate a kind of pagination: I mean showing as many numbers as news
I first tried a for-loop

<?php for($i=1; $i<= sizeof(mysql_fetch_array($queryNews)); $i++){ ?>
    <div class="num_txt"><?php echo $i ?></div>
<?php } ?>

No success. so I tried an similar way as the first one, also without success.

    <?php 
        $i=1;
        while($row = mysql_fetch_array($queryNews)){    ?>
        echo '<script language="javascript">confirm('.$i.')</script>;';
            <div class="num_txt"><?php echo $i ?></div>
   <?php $i++; } ?>

Does anyone knows what I’m doing wrong??
Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-26T01:05:20+00:00Added an answer on May 26, 2026 at 1:05 am

    Your for loop was almost correct, but sizeof(mysql_fetch_array($queryNews)) fetches a row from the result set and returns the number of columns in that row. You want the number of rows in the result set:

    <?php for($i=1, $numRows = mysql_num_rows($queryNews); $i<= $numRows; $i++){ ?>
        <div class="num_txt"><?php echo $i ?></div>
    <?php } ?>
    
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