Question

I’m new in PHP and I’m getting this error:

Notice: Undefined index: productid in /var/www/test/modifyform.php on
line 32

Notice: Undefined index: name in /var/www/test/modifyform.php on line
33

Notice: Undefined index: price in /var/www/test/modifyform.php on line
34

Notice: Undefined index: description in /var/www/test/modifyform.php
on line 35

I couldn’t find any solution online, so maybe someone can help me.

Here is the code:

<form action="<?php echo $_SERVER['PHP_SELF'];?>" method="POST">
   <input type="hidden" name="rowID" value="<?php echo $rowID;?>">

   <p>
      Product ID:<br />
      <input type="text" name="productid" size="8" maxlength="8" value="<?php echo $productid;?>" />
   </p>

   <p>
      Name:<br />
      <input type="text" name="name" size="25" maxlength="25" value="<?php echo $name;?>" />
   </p>

   <p>
      Price:<br />
      <input type="text" name="price" size="6" maxlength="6" value="<?php echo $price;?>" />
   </p>

   <p>
      Description:<br />
      <textarea name="description" rows="5" cols="30">
      <?php echo $description;?></textarea>
   </p>

   <p>
      <input type="submit" name="submit" value="Submit!" />
   </p>
   </form>
   <?php
   if (isset($_POST['submit'])) {
      $rowID = $_POST['rowID'];
      $productid = $_POST['productid']; //this is line 32 and so on...
      $name = $_POST['name'];
      $price = $_POST['price'];
      $description = $_POST['description'];

}

What I do after that (or at least I’m trying) is to update a table in MySQL.
I really can’t understand why $rowID is defined while the other variables aren’t.

Thank you for taking your time to answer me.
Cheers!

Answer 1

Try:

<?php

if (isset($_POST['name'])) {
    $name = $_POST['name'];
}

if (isset($_POST['price'])) {
    $price = $_POST['price'];
}

if (isset($_POST['description'])) {
    $description = $_POST['description'];
}

?>