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Home/ Questions/Q 3878356
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T22:36:12+00:00 2026-05-19T22:36:12+00:00

I’m new to C++ programming, so maybe you’d find my question too stupid. Sorry

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I’m new to C++ programming, so maybe you’d find my question too stupid. Sorry about that, but I’d like to know how to implement this Java-style structure:

#include "B";
class A {
   B objB;
}
---
#include "A";
class B {
   A objA;
}

The compiler going crazy trying to understand this code. Could you please advise me about a possible solution? Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-19T22:36:13+00:00Added an answer on May 19, 2026 at 10:36 pm

    This code is illegal in C++ and the compiler is right to reject it. The problem is that if you have a concrete object of type A inside of an object of type B and vice-versa, then there is no meaningful definition of the size of either object. In particular, objects in C++ must each be at least one byte in size. Therefore, given an object of type A (call it a), there must be one byte of storage for a, a.objB.objA, a.objB.objA.objB.objA, etc. In fact, you’d need infinite storage space, because there’s always an object nested further inside of these objects!

    To fix this, you’ll want to change this so that you’re storing pointers to objects of type B and A in A and B, respectively. This breaks the chain because while an A* pointer points to an A object, the pointer itself isn’t an A object and thus uses only four bytes. Once you have this, you can use forward declarations to declare these pointers. For example:

    File: A.h:

    class B;
    class A {
         B* objB;
    };
    

    File: B.h:

    class A;
    class B {
         A* objA;
    };
    

    Hope this helps!

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