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Home/ Questions/Q 728251
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T06:39:36+00:00 2026-05-14T06:39:36+00:00

I’m new to C++, so bear with me. I have a generic class called

  • 0

I’m new to C++, so bear with me. I have a generic class called A. A has a nested class called B. A contains a method called getB(), which is supposed to return a new instance of B. However, I can’t get my code to compile. Here’s what it looks like:#include

A.h

template <class E>
class A {

public:
    class B {
    public:
        int data;
    };

    B * getB(); 
};

A.cpp

#include "A.h"

template <class E>
A<E>::B * A::getB() {
    return new B();
}

When I try to compile this, I get the following error:

error: expected constructor, destructor, or type conversion before '*' token

Does anybody know what I’m doing wrong?

Thanks,

helixed

UPDATE:

Thanks for the quick replies everyone. I’m still having a little trouble getting this working. After taking the suggestions listed here, I have something like this:

A.h

template <class E>
class A {

public:
    class B {
    public:
        int data;
    };

    B * getB(); 
};

template <class E>
typename A<E>::B * A<E>::getB() {
    return new B();
}

class C {

};

However, when I try to use this from main, I get an error. Here’s my main method:

main.cpp

#include "A.h"

int main(int argc, char *argv[])
{
    A<C> *a = new A<C>();
    A<C>::B *b = a.getB();
}

When I try to compile this, I get the following error:

error: request for member 'getB' in 'a', which is of non-class type 'A<C>*'

Thanks again for the quick responses.

helixed

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T06:39:37+00:00Added an answer on May 14, 2026 at 6:39 am

    The compiler isn’t smart enough to figure that “B” is a type when “A” is templated. Try using typename.

    template <class E>
    typename A<E>::B * A<E>::getB() {
        return new B();
    }
    
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