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Home/ Questions/Q 7639049
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T08:19:13+00:00 2026-05-31T08:19:13+00:00

I’m new to CoffeeScript, and I like the CoffeeScript classes, but can’t work out

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I’m new to CoffeeScript, and I like the CoffeeScript classes, but can’t work out how to extend them in jQuery using jQuery.prototype.

This is for part of my app that holds sort-of global state variables, so I want to call it via $.myThing.myFunction(), and not the usual $.fn.extend / $().myThing() extending way.

I can get it to work like this:

$ = jQuery
$.myThing = $.myThing || {}

$.extend $.myThing, {
  myProperty: 0
  myFunction: ->
}

Which is okay, but then I can’t use it as a class, and the structure doesn’t look pretty my pycharm. (Which, being honest is probably bothering more than the whole class thing…)

What I want, is to do something like this:

$ = jQuery
$.myThing = $.myThing || {}

class myThing
  myProperty: 0
  myFunction: ->

$.extend $.myThing, myThing()

But it doesn’t work (other than looking pretty in pycharm). Is there a better way to do this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T08:19:14+00:00Added an answer on May 31, 2026 at 8:19 am

    Would this work for you?

    class jQuery.myThing
      myProperty: 0
      myFunction: ->
    

    Compiles to:

    jQuery.myThing = (function() {
    
      function myThing() {}
    
      myThing.prototype.myProperty = 0;
    
      myThing.prototype.myFunction = function() {};
    
      return myThing;
    
    })();
    

    Edit: $.myThing as an instance of the class:

    class myThing
      myProperty: 0
      myFunction: ->
    
    jQuery.myThing = new myThing
    
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