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Home/ Questions/Q 8121945
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T05:40:18+00:00 2026-06-06T05:40:18+00:00

I’m new to Django, and try to develop my resume online. Here it is

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I’m new to Django, and try to develop my resume online.

Here it is my two models :

#MODELS
class Category( models.Model ):
    help_text = 'Category respresents a category of experience, or school experiments'
    # Name
    name = models.CharField( max_length=500, blank=False )
    # ...

    def __unicode__( self ):
        return self.name


class Experience( models.Model ):
    help_text = 'An experience can be a skill, a school experiment etc.'
    # ordering = ['-end_date']
    parent_category = models.ForeignKey( Category )
    # Name
    # ...
    end_date = models.DateField( 'date of end', blank=True, null=True )
    # ...

    def __unicode__(self):
        return self.name

#View
# index view
def index( request ):
        # Would like something to just order the children
    all_categories = Category.objects.filter().order_by( ???? )
    return render_to_response( 'CMSCV/index.html',
            { 'categories' : all_categories },
            context_instance=RequestContext(request) )

As you can see in my view, I don’t know how to sort only the children (experience) by the field “end_date” in the query.

I tried this:

Category.objects.all().order_by( 'experience__end_date' ).distinct()

Category.objects.all().order_by( 'experience__end_date' ).distinct('experience__end_date')

Category.objects.all().order_by( 'experience__end_date' ).distinct( 'name' )

But it returns me too many parents…

Would like to know how can I solve it ?

Thank you

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T05:40:20+00:00Added an answer on June 6, 2026 at 5:40 am

    You can use Django’s aggregations for this to get the max end_date and then sort on it. For example:

    from django.db.models import Max
    Category.objects.all().annotate(max_date=Max('experiences_set__end_date')).order_by('max_date')
    
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