Question

I’m new to Haskell and I’d like to be able to time the runtime of a given function call or snippet of code.

In Clojure I can use ‘time’:

user=> (time (apply * (range 2 10000)))
"Elapsed time: 289.795 msecs"
2846259680917054518906413212119868890148051...

In Scala, I can define the function myself:

scala> def time[T](code : => T) =  {
     |   val t0 = System.nanoTime : Double
     |   val res = code
     |   val t1 = System.nanoTime : Double
     |   println("Elapsed time " + (t1 - t0) / 1000000.0 + " msecs")
     |   res
     | }
time: [T](=> T)T

scala> time((1 to 10000).foldLeft(1:BigInt)(_*_))
Elapsed time 274.292224 msecs
res0: BigInt = 284625968091705451...

How can I write the equivalent of my Scala function or Clojure’s ‘time’ in Haskell? The System.TimeIt module I’ve found on Hackage is not general enough because it works only if an IO computation is being measured. So timeIt(4 + 4) wouldn’t work, only timeIt(print $ 4 + 4), which gets annoying fast. Beside, I really want to see how Haskell handles the general case.

Thank you!

Answer 1

Please look at using the standard libraries for this:

• Timing computations in Haskell
• Criterion, possibly the best open source benchmarking/timing library in existence
• About Criterion

Just use criterion.

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A note on evaluation depth: laziness means you need to decide how much evaluation you want to have during your timing run. Typically you’ll want to reduce your code to normal form. The NFData typeclass lets you do this via the rnf method. If evaluating to the outermost constructor is ok, use seq on your pure code to force its evaluation.