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Home/ Questions/Q 8875957
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T19:06:19+00:00 2026-06-14T19:06:19+00:00

I’m new to Java and I have struck with some doubt. For example, consider

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I’m new to Java and I have struck with some doubt. For example, consider the expression like:

a.method()
a.method("string")

people call them “dynamic dispatch”. But I’m sure that the type checker makes sure that the methods named method(),method(String a) available for object a.

But why does it called “dynamic”? It isn’t static call? Since the compiler found that already?

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  1. Editorial Team
    Editorial Team
    2026-06-14T19:06:20+00:00Added an answer on June 14, 2026 at 7:06 pm

    The example that you have posted will not use dynamic dispatch. You have posted an example of Method Overloading. And decision of method invocation in case of Overloading is done at compile time. It is on the compiler to decide which method will be invoked based on the formal parameters and the actual arguments passed.


    Dynamic Binding comes into play when you are working with Method Overriding, where the decision of which method will actually be invoked is delayed till runtime.

    For e.g: –

    class A {
        public void demo() { }
    }
    
    class B extends A {
        public void demo() { }
    }
    
    public class Test {
        public static void main(String[] args) {
            A a = new B();
            a.demo();   // B class method will be invoked.
    
            A obj = new A();
            obj.demo();  // A class method will be invoked.
        }
    }
    

    The decision of which method is invoked is decided on the basis of which class instance the particular reference is pointing to, And that is only known at runtime. And hence Dynamic Dispatch.

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