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Home/ Questions/Q 6360937
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T23:42:45+00:00 2026-05-24T23:42:45+00:00

I’m new to jQuery and I don’t know what is the best function to

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I’m new to jQuery and I don’t know what is the best function to replace this:

<span id="fcp-vicon" onClick="be_visible()"><img src="'.$path.'img/blueicons/hidden.jpg" alt="Cambiar a Modo Visible"/></span>

With this:

<span id="fcp-vicon" onClick="be_hidden()"><img src="'.$path.'img/blueicons/visible.jpg" alt="Cambiar a Modo Invisible"/></span>

The idea is that image works like a switch to toggle the visibility of other field.

Thank you very much.


Thanks, I need to change the span itself, so I need to change the related image and the inline onClick event.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T23:42:46+00:00Added an answer on May 24, 2026 at 11:42 pm

    To add to loktar’s answer…

    I assume what you want is an image that toggles the visibility of something else (lets say a div).

    What you need is this html:

    <span id="fcp-vicon"><img src="'.$path.'img/blueicons/visible.jpg" alt="Cambiar a Modo Invisible"/></span>
    

    and something like this jquery:

    $(document).ready(function(){
        // catch the click on the icon
        $('#fcp-vicon').click(function(){
            // toggle the visibility of the other element
            $('#id-of-other-element').toggle();
        });
    });
    

    With jquery there is no need for inline javascript! 🙂

    EDIT

    Sorry, didn’t realise you were changing the image each time…

    Ok the best way to do this is to have two images in your span! 🙂

    <span id="fcp-vicon">
        <img src="'.$path.'img/blueicons/visible.jpg" alt="Cambiar a Modo Invisible"/>
        <img src="'.$path.'img/blueicons/hidden.jpg" alt="Cambiar a Modo Invisible" style="display:none"/>
    </span>
    

    And jquery:

    $(document).ready(function(){
        // catch the click on the icon
        $('#fcp-vicon').click(function(){
            // toggle the visibility of the images contained in it
            $(this).find('img').toggle();
            // because the first image is showing and the second hidden
            // when you do this the first image will toggle to hidden
            // and the next one will toggle to visible.
        });
    });
    

    This might help: http://jsfiddle.net/tclayson/tPWNN/

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