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Home/ Questions/Q 4073726
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T17:03:52+00:00 2026-05-20T17:03:52+00:00

I’m new to PHP, so I’m not exactly sure how it works. Anyway, I

  • 0

I’m new to PHP, so I’m not exactly sure how it works.

Anyway, I would line to return a multidimensional array to another method, essentially something storing a small amount of record and columns, table like structure.

I’ve written the following, no warning but no data either

public function GetData($sqlquery)
{
    include 'config.php';

    $result = mysql_query($sqlquery,$con);
    $data = array();

    while($row = mysql_fetch_assoc($result))
    {
        $data[] = $row;
    }

    return $data;
}

Most likely doing something stupid

Help appreciated.

EDIT:

Thanks for all the fast replies

I figured out why this wasn’t working, I was addressing the array as such

print $data[0][0];

Rather than

print $data[0]['title']; 

for example, thanks all 🙂

PS I really find it hard to believe you can’t say $data[0][5], It’s more logical IMO than specifying a string value for location

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  1. Editorial Team
    Editorial Team
    2026-05-20T17:03:53+00:00Added an answer on May 20, 2026 at 5:03 pm

    Your code seems okay. At least, you’re going in right direction.

    Just some minor corrections:

    • NEVER include config inside of a function. it should be done in class constructor
    • if you really want to use connection identifier – make it class variable. But for most applications using single connection to db its unnecessary to use $con, so you can omit it
    • error handling is absolutely necessary

    so,

    public function GetData($sqlquery)
    {
        $data = array();
        $result = mysql_query($sqlquery) or trigger_error(mysql_error().$sqlquery);
        if ($result)
        {
            while($row = mysql_fetch_assoc($result))
            {
                $data[] = $row;
            }
        }
        return $data;
    }
    

    run this code and see what it says.

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