Question

I’m new to php so pardon the ignorance
I’m trying to include a php variable, it is and is not working.

$currentdata = file_get_contents("http://www.abr.business.gov.au/abnDetails.aspx?abn=$abn");

This works with $abn being the variable being passed from earlier being set.

$abntypedata = '/d$abn&amp;ResultListURL=">(.+?)</'; This does not work.
$abntypedata = '/d33051775556&amp;ResultListURL=">(.+?)</'; This does.

I need to be able to use the variable $abn to insert that number as it will be user defined. Why is this not working?

Answer 1

Php is perticular about the quotations. You have to use double quotes to include variables:

$abntypedata = "/d$abn&amp;ResultListURL=\">(.+?)</"; This works

or

$abntypedata = '/d'.$abn.'&amp;ResultListURL=">(.+?)</'; This works