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Home/ Questions/Q 7572027
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T15:49:13+00:00 2026-05-30T15:49:13+00:00

I’m new to PHP so this question seems stupid, but suppose I’m assigning variable

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I’m new to PHP so this question seems stupid, but suppose I’m assigning variable ABC with value to be a new object of class XYZ, then how could I get the name “ABC” inside XYZ’s class definition ?

$ABC = new XYZ;
$ABC->echoInstanceName(); //--I wish this line could echo out : ABC

Is this easier when the instance is assigned to an array’s element ?

$ABC = array('myElem'=>new XYZ);
$ABC['myElem']->echoInstanceName(); //--I wish this line could echo out : ABC

All suggestions appreciated !


More infos : I’m doing kind of thing: build a system of animals.

Started with class nativeAnimal & extended to Monkey, Elephant, Fish…etc. And in runtime, I create a 2-tiers array that each array’s element is an instance of type Monkey, Elephant, or Fish…

I want the array’s key is the animal’s name. And inside the class Monkey, I want a function to echo the Monkey’s name. Of course I can pass the array’s key to the instance somehow, but I want to avoid typing it twice. (That can lead to error(s) later when I change just one name)

Is this so impossible ? Or could you please suggest a better pattern ? Thanks !

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  1. Editorial Team
    Editorial Team
    2026-05-30T15:49:14+00:00Added an answer on May 30, 2026 at 3:49 pm

    You cannot do this. If you want to pass ABC value to the XYZ class, do it with an extra argument in constructor:

    $ABC = new XYZ('ABC');
    

    There is no other way to inform class about variable that it was assigned to.

    Example XYZ class:

    class XYZ {
      protected $name;
      public __construct($name) {
        $this->name = $name;
      }
    
      public echoInstanceName() {
        echo $name;
      }
    
      public getName() {
        return $this->name;
      }
    }
    
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