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Home/ Questions/Q 9243389
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T08:48:00+00:00 2026-06-18T08:48:00+00:00

I’m new to PHP Unit and now I have a dilemma. Function structure is

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I’m new to PHP Unit and now I have a dilemma.

Function structure is something like this:

function myfunc($arg) {
  $data = $anotherobject->myfunc2($arg);
  $diffdata = $anotherobject->myfunc3($arg);
  return $data. " ".arg. " ". $diffdata;
}

How can I verifiy that the output is what it should be?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T08:48:01+00:00Added an answer on June 18, 2026 at 8:48 am

    Edit:
    Jasir is of course also right. The point of unittesting is to test a unit as small as possible. So you would also make tests to cover myfunc2() and myfunc3().

    End of edit

    Using a stub, you can set myfunc2() and myfunc3() to return a known value. You can then assert the return of myfunc as you would normally do.

    Something along the lines of:

    <?php
    require_once 'SomeClass.php';
    
    class StubTest extends PHPUnit_Framework_TestCase
    {
        public function testStub()
        {
               // Create a stub for the SomeClass class.
               $stub = $this->getMock('SomeClass');
    
               // Configure the stub.
               $stub->expects($this->any())
                   ->method('myfunc2')
                   ->will($this->returnValue('foo'));
    
               $stub->expects($this->any())
                   ->method('myfunc3')
                   ->will($this->returnValue('bar'));
    
                // Calling $stub->doSomething() will now return
                // 'foo'.
                $this->assertEquals('foo somearg bar', $stub->myfunc('somearg'));
            }
        }
    ?>
    
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