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Editorial Team
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Asked: 2026-05-16T10:55:14+00:00

I’m new to Python and I have been trying to search through html with

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I’m new to Python and I have been trying to search through html with regular expressions that has been parsed with BeautifulSoup. I haven’t had any success and I think the reason is that I don’t completely understand how to set up the regular expressions properly. I’ve looked at older questions about similar problems but I still haven’t figured it out. If somebody could extract the “/torrent/32726/0/” and “Slackware Linux 13.0 [x86 DVD ISO]” as well as a detailed expression of how the regular expression works, it would be really helpful.

<td class="name">
  <a href="/torrent/32726/0/">
   Slackware Linux 13.0 [x86 DVD ISO]
  </a>
 </td>

Edit: What I meant to say is, I am trying to extract “/torrent/32726/0/” and “Slackware Linux 13.0 [x86 DVD ISO]” using BeautifulSoups functions to search the parse tree. I’ve been trying various things after searching and reading the documentation, but I’m still not sure on how to go about it.

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1 Answer

  1. Editorial Team

    BeautifulSoup could also extract node values from your html.

    from BeautifulSoup import BeautifulSoup

html = ('<html><head><title>Page title</title></head>'
       '<body>'
       '<table><tr>'
       '<td class="name"><a href="/torrent/32726/0/">Slackware Linux 13.0 [x86 DVD ISO]</a></td>'
       '<td class="name"><a href="/torrent/32727/0/">Slackware Linux 14.0 [x86 DVD ISO]</a></td>'
       '<td class="name"><a href="/torrent/32728/0/">Slackware Linux 15.0 [x86 DVD ISO]</a></td>'
       '</tr></table>'
       'body'
       '</html>')
soup = BeautifulSoup(html)
links = [td.find('a') for td in soup.findAll('td', { "class" : "name" })]
for link in links:
    print link.string

    Output: 

    Slackware Linux 13.0 [x86 DVD ISO]  
Slackware Linux 14.0 [x86 DVD ISO]  
Slackware Linux 15.0 [x86 DVD ISO]
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