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Home/ Questions/Q 6731529
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T10:32:24+00:00 2026-05-26T10:32:24+00:00

I’m new to python, and I have the following problem: I am trying to

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I’m new to python, and I have the following problem: I am trying to minimize a python function that has a numpy array as one of its arguments. When I use scipy.optimize.fmin, it turns my array into a list (which results in the function failing to evaluate). Is there an optimization function that does accept numpy arrays as function arguments?

Thanks in advance!

-MB

Edit: Here is an example of what I’m talking about, courtesy of @EOL:

import scipy.optimize as optimize
import numpy as np

def rosen(x):
    print x
    x=x[0]
    """The Rosenbrock function"""
    return sum(100.0*(x[1:]-x[:-1]**2.0)**2.0 + (1-x[:-1])**2.0)
x0 = np.array([[1.3, 0.7, 0.8, 1.9, 1.2]])
xopt = optimize.fmin(rosen, x0, xtol=1e-8, disp=True)
#[ 1.3  0.7  0.8  1.9  1.2]
#(note that this used to be a numpy array of length 0, 
#now it's "lost" a set of brackets")
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  1. Editorial Team
    Editorial Team
    2026-05-26T10:32:24+00:00Added an answer on May 26, 2026 at 10:32 am

    Here is an example using optimize.fmin which comes from the scipy tutorial:

    import scipy.optimize as optimize
    def rosen(x):
        """The Rosenbrock function"""
        return sum(100.0*(x[1:]-x[:-1]**2.0)**2.0 + (1-x[:-1])**2.0)
    x0 = [1.3, 0.7, 0.8, 1.9, 1.2]
    xopt = optimize.fmin(rosen, x0, xtol=1e-8, disp=True)
    # Optimization terminated successfully.
    #          Current function value: 0.000000
    #          Iterations: 339
    #          Function evaluations: 571
    print(xopt)
    # [ 1.  1.  1.  1.  1.]
    

    Does this help? If not, can you modify this example to show what is turning into a list?

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