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Home/ Questions/Q 9255685
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T11:46:00+00:00 2026-06-18T11:46:00+00:00

I’m new to python and I keep getting an error doing the simpliest thing.

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I’m new to python and I keep getting an error doing the simpliest thing.

I’m trying to use a variable in a regular expression and replace that with an *

the following gets me the error “TypeError: not all arguments converted during string formatting” and I can’t tell why. this should be so simple.

import re
file = "my123filename.zip"
pattern = "123"
re.sub(r'%s', "*", file) % pattern

Error:
Traceback (most recent call last):
File “”, line 1, in ?
TypeError: not all arguments converted during string formatting

Any tips?

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  1. Editorial Team
    Editorial Team
    2026-06-18T11:46:02+00:00Added an answer on June 18, 2026 at 11:46 am

    You’re problem is on this line:

    re.sub(r'%s', "*", file) % pattern
    

    What you’re doing is replacing every occurance of %s with * in the text from the string file (in this case, I’d recommend renaming the variable filename to avoid shadowing the builtin file object and to make it more explicit what you’re working with). Then you’re trying to replace the %s in the (already replaced) text with pattern. However, file doesn’t have any format modifiers in it which leads to the TypeError you see. It’s basically the same as:

    'this is a string' % ("foobar!")
    

    which will give you the same error.

    What you probably want is something more like:

    re.sub(str(pattern),'*',file)
    

    which is exactly equivalent to:

    re.sub(r'%s' % pattern,'*',file)
    
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