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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T22:14:06+00:00 2026-06-14T22:14:06+00:00

I’m new to ruby and I’m trying to solve a problem. I’m parsing through

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I’m new to ruby and I’m trying to solve a problem.

I’m parsing through several text field where I want to remove the header which has different values. It works fine when the header always is the same:

variable = variable.gsub(/(^Header_1:$)/, '')

But when I put in several arguments it doesn’t work:

variable = variable.gsub(/(^Header_1$)/ || /(^Header_2$)/ || /(^Header_3$)/ || /(^Header_4$)/ || /^:$/, '')
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  1. Editorial Team
    Editorial Team
    2026-06-14T22:14:07+00:00Added an answer on June 14, 2026 at 10:14 pm

    You can use Regexp.union:

    regex = Regexp.union(
      /^Header_1/,
      /^Header_2/,
      /^Header_3/,
      /^Header_4/,
      /^:$/
    )
    variable.gsub(regex, '')
    

    Please note that ^something$ will not work on strings containing something more than something 🙂

    Cause ^ is for matching beginning of string and $ is for end of string.

    So i intentionally removed $.

    Also you do not need brackets when you only need to remove the matched string.

    You can also use it like this:

    headers = %w[Header_1 Header_2 Header_3]
    regex = Regexp.union(*headers.map{|s| /^#{s}/}, /^\:$/, /etc/)
    variable.gsub(regex, '')
    

    And of course you can remove headers without explicitly define them.

    Most likely there are a white space after headers?

    If so, you can do it as simple as:

    variable = "Header_1 something else"
    puts variable.gsub(/(^Header[^\s]*)?(.*)/, '\2')
    #=>  something else
    
    variable = "Header_BLAH something else"
    puts variable.gsub(/(^Header[^\s]*)?(.*)/, '\2')
    #=>  something else
    
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