Question

I’m new to scala. I tried this code:

val name = "mike"
println(name.getClass())

It’s OK and printed java.lang.String

But, when I try:

val num = 123
println(num.getClass())

There is such a compiler error:

type mismatch; found : Int required: ?{val getClass: ?} Note: primitive types are not implicitly 
 converted to AnyRef. You can safely force boxing by casting x.asInstanceOf[AnyRef].

I remember scala said “Everything is object in scala”, why can’t I invoke num.getClass()? And how to fix it?

Answer 1

Yep, everything is an object, but not necessary an instance of a java class/something with a getClass() method 🙂

Java primitive values (and Unit) are AnyVals in scala (instances of so called value classes), and – whenever it’s possible – they are compiled to Java primitives at the end. When it’s not possible boxing is done (similar to auto boxing in Java). But – as the error reports – boxing did not happen (“implicitly”) in your case. Value classes don’t have a getClass() method -> compilation error.

Java classes are AnyRefs (an instance of a reference class = a class instance in Java). getClass will work fine on them: AnyRef is practically the same as java.lang.Object -> it also has a getClass() method that you can call.

As the error recommends you can force the boxing, then getClass() will work on it:

num.asInstanceOf[AnyRef].getClass

will print

class java.lang.Integer

If you want to avoid boxing (e.g. you want to differentiate between primitive and boxed values) have a look at HowTo get the class of _ :Any