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Home/ Questions/Q 7185349
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T18:23:45+00:00 2026-05-28T18:23:45+00:00

Im new using Python, now I have a problem using ElementTree and read out

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Im new using Python, now I have a problem using ElementTree and read out values from an xml with this structure:

<entry number="47" date="2011-01-29">
    <name>Swedbank-taxe</name>
    <row account="1930" debit="0" credit="16712"/>
    <row account="8415" debit="1781" credit="0"/>
    <row account="2734" debit="14931" credit="0"/>
</entry>
<entry number="48" date="2011-01-29">
    <name>Agri - Calcium</name>
    <row account="1930" debit="0" credit="2000"/>
    <row account="1471" debit="400" credit="0"/>
    <row account="4370" debit="1600" credit="0"/>
</entry>

With this code I try to print out the content of every row with the label="row":

from tkinter import filedialog
from xml.etree.ElementTree import ElementTree as ET
xmltree = ET()
filval=filedialog.askopenfilename()
xmltree.parse(filval)
konton = xmltree.getiterator('row')
for i in konton:
    print (i.text)

But the only print out is None.

Do you know what I’m doing wrong?
Also I would like to print out every row with account="1930". In this case I would like a print out like this:

1930
1930
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  1. Editorial Team
    Editorial Team
    2026-05-28T18:23:46+00:00Added an answer on May 28, 2026 at 6:23 pm
    from tkinter import filedialog
    from xml.etree.ElementTree import ElementTree as ET
    xmltree = ET()
    filval=filedialog.askopenfilename()
    xmltree.parse(filval)
    konton = xmltree.getiterator('row')
    for i in konton:
        # remove this to print the account from every row
        if i.attrib['account'] == "1930":
            print (i.attrib['account'])
    
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